11p^2=99=0

Solution for 11p^2=99=0 equation:

11p^2=99=0

We move all terms to the left:

11p^2-(99)=0

a = 11; b = 0; c = -99;
Δ = b2-4ac
Δ = 02-4·11·(-99)
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4356}=66$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-66}{2*11}=\frac{-66}{22}
=-3
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+66}{2*11}=\frac{66}{22}
=3
$